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6331302110681 is a prime number
BaseRepresentation
bin101110000100001111100…
…0000110110010111011001
3211102021012022220120001222
41130020133000312113121
51312213001320020211
621244320545021425
71222264365663452
oct134103700662731
924367168816058
106331302110681
1120210a9a91809
12863070324875
1336c06824a392
1417c61828a129
15aea5972b1db
hex5c21f0365d9

6331302110681 has 2 divisors, whose sum is σ = 6331302110682. Its totient is φ = 6331302110680.

The previous prime is 6331302110593. The next prime is 6331302110713. The reversal of 6331302110681 is 1860112031336.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4805543544025 + 1525758566656 = 2192155^2 + 1235216^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-6331302110681 is a prime.

It is a super-2 number, since 2×63313021106812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (6331302115681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3165651055340 + 3165651055341.

It is an arithmetic number, because the mean of its divisors is an integer number (3165651055341).

Almost surely, 26331302110681 is an apocalyptic number.

It is an amenable number.

6331302110681 is a deficient number, since it is larger than the sum of its proper divisors (1).

6331302110681 is an equidigital number, since it uses as much as digits as its factorization.

6331302110681 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 6331302110681 in words is "six trillion, three hundred thirty-one billion, three hundred two million, one hundred ten thousand, six hundred eighty-one".