Base | Representation |
---|---|
bin | 11100110010101010010100… |
… | …11110000101011110001101 |
3 | 22022011200212002010112221211 |
4 | 32121111022132011132031 |
5 | 31244311231222423203 |
6 | 342353431311454421 |
7 | 16223145066043231 |
oct | 1631251236053615 |
9 | 268150762115854 |
10 | 63313362311053 |
11 | 191a00564a3158 |
12 | 7126678b27411 |
13 | 294356968560a |
14 | 118c5512905c1 |
15 | 74bdd4b23c6d |
hex | 39954a78578d |
63313362311053 has 16 divisors (see below), whose sum is σ = 65532258842112. Its totient is φ = 61105593528000.
The previous prime is 63313362311051. The next prime is 63313362311141. The reversal of 63313362311053 is 35011326331336.
It is a cyclic number.
It is not a de Polignac number, because 63313362311053 - 21 = 63313362311051 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 63313362310997 and 63313362311015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (63313362311051) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39449463 + ... + 41023003.
It is an arithmetic number, because the mean of its divisors is an integer number (4095766177632).
Almost surely, 263313362311053 is an apocalyptic number.
It is an amenable number.
63313362311053 is a deficient number, since it is larger than the sum of its proper divisors (2218896531059).
63313362311053 is a wasteful number, since it uses less digits than its factorization.
63313362311053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1577076.
The product of its (nonzero) digits is 262440, while the sum is 40.
Adding to 63313362311053 its reverse (35011326331336), we get a palindrome (98324688642389).
The spelling of 63313362311053 in words is "sixty-three trillion, three hundred thirteen billion, three hundred sixty-two million, three hundred eleven thousand, fifty-three".
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