Base | Representation |
---|---|
bin | 111010111101110001… |
… | …111111001111011001 |
3 | 20001102102121002012001 |
4 | 322331301333033121 |
5 | 2014131231240212 |
6 | 45030312521001 |
7 | 4400653132225 |
oct | 727561771731 |
9 | 201372532161 |
10 | 63313540057 |
11 | 2493a92a819 |
12 | 1032b6b0161 |
13 | 5c800a0491 |
14 | 30c8995785 |
15 | 19a85cc657 |
hex | ebdc7f3d9 |
63313540057 has 2 divisors, whose sum is σ = 63313540058. Its totient is φ = 63313540056.
The previous prime is 63313540013. The next prime is 63313540063. The reversal of 63313540057 is 75004531336.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 59290302016 + 4023238041 = 243496^2 + 63429^2 .
It is a cyclic number.
It is not a de Polignac number, because 63313540057 - 211 = 63313538009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 63313539998 and 63313540025.
It is not a weakly prime, because it can be changed into another prime (63313540097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31656770028 + 31656770029.
It is an arithmetic number, because the mean of its divisors is an integer number (31656770029).
Almost surely, 263313540057 is an apocalyptic number.
It is an amenable number.
63313540057 is a deficient number, since it is larger than the sum of its proper divisors (1).
63313540057 is an equidigital number, since it uses as much as digits as its factorization.
63313540057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 113400, while the sum is 37.
The spelling of 63313540057 in words is "sixty-three billion, three hundred thirteen million, five hundred forty thousand, fifty-seven".
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