Search a number
-
+
6331364649817 is a prime number
BaseRepresentation
bin101110000100010001010…
…1111011010101101011001
3211102021100200120212122021
41130020202233122231121
51312213113322243232
621244331101254441
71222266055364344
oct134104257325531
924367320525567
106331364649817
112021131317349
12863089264421
1336c0781a5c9c
1417c6226c945b
15aea5ee81397
hex5c222bdab59

6331364649817 has 2 divisors, whose sum is σ = 6331364649818. Its totient is φ = 6331364649816.

The previous prime is 6331364649721. The next prime is 6331364649851. The reversal of 6331364649817 is 7189464631336.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6264888856576 + 66475793241 = 2502976^2 + 257829^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-6331364649817 is a prime.

It is not a weakly prime, because it can be changed into another prime (6331364649017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3165682324908 + 3165682324909.

It is an arithmetic number, because the mean of its divisors is an integer number (3165682324909).

Almost surely, 26331364649817 is an apocalyptic number.

It is an amenable number.

6331364649817 is a deficient number, since it is larger than the sum of its proper divisors (1).

6331364649817 is an equidigital number, since it uses as much as digits as its factorization.

6331364649817 is an evil number, because the sum of its binary digits is even.

The product of its digits is 47029248, while the sum is 61.

The spelling of 6331364649817 in words is "six trillion, three hundred thirty-one billion, three hundred sixty-four million, six hundred forty-nine thousand, eight hundred seventeen".