Search a number
-
+
633671303249 is a prime number
BaseRepresentation
bin10010011100010011100…
…00001100000001010001
32020120121122100111010202
421032021300030001101
540340224323200444
61203034331104545
763531652130615
oct11161160140121
92216548314122
10633671303249
11224813a27046
12a29872a2155
13479a780949a
142295411d345
151173ae4034e
hex9389c0c051

633671303249 has 2 divisors, whose sum is σ = 633671303250. Its totient is φ = 633671303248.

The previous prime is 633671303207. The next prime is 633671303261. The reversal of 633671303249 is 942303176336.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 322814876224 + 310856427025 = 568168^2 + 557545^2 .

It is a cyclic number.

It is not a de Polignac number, because 633671303249 - 212 = 633671299153 is a prime.

It is a super-3 number, since 3×6336713032493 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (633671303269) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 316835651624 + 316835651625.

It is an arithmetic number, because the mean of its divisors is an integer number (316835651625).

Almost surely, 2633671303249 is an apocalyptic number.

It is an amenable number.

633671303249 is a deficient number, since it is larger than the sum of its proper divisors (1).

633671303249 is an equidigital number, since it uses as much as digits as its factorization.

633671303249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1469664, while the sum is 47.

The spelling of 633671303249 in words is "six hundred thirty-three billion, six hundred seventy-one million, three hundred three thousand, two hundred forty-nine".