Base | Representation |
---|---|
bin | 10010011101001001001… |
… | …00010011010000011001 |
3 | 2020121202222212012001002 |
4 | 21032210210103100121 |
5 | 40342140010000433 |
6 | 1203151121234345 |
7 | 63546054012401 |
oct | 11164444232031 |
9 | 2217688765032 |
10 | 634121171993 |
11 | 224a249630a1 |
12 | a2a91a929b5 |
13 | 47a49a8b4ca |
14 | 22997b85801 |
15 | 117656a49e8 |
hex | 93a4913419 |
634121171993 has 2 divisors, whose sum is σ = 634121171994. Its totient is φ = 634121171992.
The previous prime is 634121171933. The next prime is 634121172001. The reversal of 634121171993 is 399171121436.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 574013823769 + 60107348224 = 757637^2 + 245168^2 .
It is a cyclic number.
It is not a de Polignac number, because 634121171993 - 226 = 634054063129 is a prime.
It is not a weakly prime, because it can be changed into another prime (634121171933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 317060585996 + 317060585997.
It is an arithmetic number, because the mean of its divisors is an integer number (317060585997).
Almost surely, 2634121171993 is an apocalyptic number.
It is an amenable number.
634121171993 is a deficient number, since it is larger than the sum of its proper divisors (1).
634121171993 is an equidigital number, since it uses as much as digits as its factorization.
634121171993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 244944, while the sum is 47.
The spelling of 634121171993 in words is "six hundred thirty-four billion, one hundred twenty-one million, one hundred seventy-one thousand, nine hundred ninety-three".
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