Base | Representation |
---|---|
bin | 111011001000100110… |
… | …001101000001000011 |
3 | 20001220002001012121112 |
4 | 323020212031001003 |
5 | 2020014210001011 |
6 | 45100314113535 |
7 | 4405315411313 |
oct | 731046150103 |
9 | 201802035545 |
10 | 63495000131 |
11 | 24a232aa422 |
12 | 1038041b8ab |
13 | 5cab865ac4 |
14 | 3104b0d443 |
15 | 19b94c358b |
hex | ec898d043 |
63495000131 has 2 divisors, whose sum is σ = 63495000132. Its totient is φ = 63495000130.
The previous prime is 63495000097. The next prime is 63495000157. The reversal of 63495000131 is 13100059436.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 63495000131 - 210 = 63494999107 is a prime.
It is a super-2 number, since 2×634950001312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (63495000161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31747500065 + 31747500066.
It is an arithmetic number, because the mean of its divisors is an integer number (31747500066).
Almost surely, 263495000131 is an apocalyptic number.
63495000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
63495000131 is an equidigital number, since it uses as much as digits as its factorization.
63495000131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 32.
Adding to 63495000131 its reverse (13100059436), we get a palindrome (76595059567).
The spelling of 63495000131 in words is "sixty-three billion, four hundred ninety-five million, one hundred thirty-one", and thus it is an aban number.
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