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63503431116241 is a prime number
BaseRepresentation
bin11100111000001100010110…
…11101000010010111010001
322022211212110022010021022011
432130012023131002113101
531310420011331204431
6343021023513542521
716242654136164424
oct1634061335022721
9268755408107264
1063503431116241
1119263721374736
127157482714a41
13295846a32804c
1411978223dd9bb
15751d0b27bcb1
hex39c18b7425d1

63503431116241 has 2 divisors, whose sum is σ = 63503431116242. Its totient is φ = 63503431116240.

The previous prime is 63503431116211. The next prime is 63503431116253. The reversal of 63503431116241 is 14261113430536.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 58643738726400 + 4859692389841 = 7657920^2 + 2204471^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-63503431116241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 63503431116194 and 63503431116203.

It is not a weakly prime, because it can be changed into another prime (63503431116211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31751715558120 + 31751715558121.

It is an arithmetic number, because the mean of its divisors is an integer number (31751715558121).

Almost surely, 263503431116241 is an apocalyptic number.

It is an amenable number.

63503431116241 is a deficient number, since it is larger than the sum of its proper divisors (1).

63503431116241 is an equidigital number, since it uses as much as digits as its factorization.

63503431116241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 40.

Adding to 63503431116241 its reverse (14261113430536), we get a palindrome (77764544546777).

The spelling of 63503431116241 in words is "sixty-three trillion, five hundred three billion, four hundred thirty-one million, one hundred sixteen thousand, two hundred forty-one".