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63743542505113 = 166277938335547
BaseRepresentation
bin11100111111001011100110…
…01101010010111010011001
322100200211020002001122002211
432133211303031102322121
531323333233340130423
6343323213522155121
716266214256260222
oct1637456315227231
9270624202048084
1063743542505113
1119346536a53a99
127195b134b2aa1
132974cb47ca043
1411a52bd7a6249
157581b0d8c10d
hex39f973352e99

63743542505113 has 4 divisors (see below), whose sum is σ = 63743582503440. Its totient is φ = 63743502506788.

The previous prime is 63743542505107. The next prime is 63743542505177. The reversal of 63743542505113 is 31150524534736.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 63743542505113 - 29 = 63743542504601 is a prime.

It is a super-2 number, since 2×637435425051132 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (63743542509113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17504995 + ... + 20830552.

It is an arithmetic number, because the mean of its divisors is an integer number (15935895625860).

Almost surely, 263743542505113 is an apocalyptic number.

It is an amenable number.

63743542505113 is a deficient number, since it is larger than the sum of its proper divisors (39998327).

63743542505113 is a wasteful number, since it uses less digits than its factorization.

63743542505113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39998326.

The product of its (nonzero) digits is 4536000, while the sum is 49.

The spelling of 63743542505113 in words is "sixty-three trillion, seven hundred forty-three billion, five hundred forty-two million, five hundred five thousand, one hundred thirteen".

Divisors: 1 1662779 38335547 63743542505113