6401300117153 has 4 divisors (see below), whose sum is σ = 6482329232640. Its totient is φ = 6320271001668.

The previous prime is 6401300117141. The next prime is 6401300117159. The reversal of 6401300117153 is 3517110031046.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 6401300117153 - 2⁶ = 6401300117089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (6401300117159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40514557625 + ... + 40514557782.

It is an arithmetic number, because the mean of its divisors is an integer number (1620582308160).

Almost surely, 2^{6401300117153} is an apocalyptic number.

It is an amenable number.

6401300117153 is a deficient number, since it is larger than the sum of its proper divisors (81029115487).

6401300117153 is an equidigital number, since it uses as much as digits as its factorization.

6401300117153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81029115486.

The product of its (nonzero) digits is 7560, while the sum is 32.

Adding to 6401300117153 its reverse (3517110031046), we get a palindrome (9918410148199).

The spelling of 6401300117153 in words is "six trillion, four hundred one billion, three hundred million, one hundred seventeen thousand, one hundred fifty-three".