Base | Representation |
---|---|
bin | 101110100111010110111… |
… | …1100101101110101111001 |
3 | 211200110211221211121110121 |
4 | 1131032231330231311321 |
5 | 1314431422420104423 |
6 | 21343112024413241 |
7 | 1230604234453543 |
oct | 135165574556571 |
9 | 24613757747417 |
10 | 6406714613113 |
11 | 2050088415a91 |
12 | 8757b7917221 |
13 | 3761c5b21799 |
14 | 18212da60693 |
15 | b19c00c645d |
hex | 5d3adf2dd79 |
6406714613113 has 2 divisors, whose sum is σ = 6406714613114. Its totient is φ = 6406714613112.
The previous prime is 6406714613099. The next prime is 6406714613129. The reversal of 6406714613113 is 3113164176046.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6312018091129 + 94696521984 = 2512373^2 + 307728^2 .
It is a cyclic number.
It is not a de Polignac number, because 6406714613113 - 213 = 6406714604921 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 6406714613113.
It is not a weakly prime, because it can be changed into another prime (6406714613213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3203357306556 + 3203357306557.
It is an arithmetic number, because the mean of its divisors is an integer number (3203357306557).
Almost surely, 26406714613113 is an apocalyptic number.
It is an amenable number.
6406714613113 is a deficient number, since it is larger than the sum of its proper divisors (1).
6406714613113 is an equidigital number, since it uses as much as digits as its factorization.
6406714613113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 217728, while the sum is 43.
Adding to 6406714613113 its reverse (3113164176046), we get a palindrome (9519878789159).
The spelling of 6406714613113 in words is "six trillion, four hundred six billion, seven hundred fourteen million, six hundred thirteen thousand, one hundred thirteen".
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