Base | Representation |
---|---|
bin | 101110100111100011001… |
… | …1011101111111111010001 |
3 | 211200111220120210211021021 |
4 | 1131033012123233333101 |
5 | 1314433243100322203 |
6 | 21343220501155441 |
7 | 1230620353220512 |
oct | 135170633577721 |
9 | 24614816724237 |
10 | 6407125401553 |
11 | 205027928a468 |
12 | 8758b13bbb81 |
13 | 37625cc6c776 |
14 | 18216c432a09 |
15 | b19e61bb5bd |
hex | 5d3c66effd1 |
6407125401553 has 2 divisors, whose sum is σ = 6407125401554. Its totient is φ = 6407125401552.
The previous prime is 6407125401533. The next prime is 6407125401571. The reversal of 6407125401553 is 3551045217046.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3925438737984 + 2481686663569 = 1981272^2 + 1575337^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6407125401553 is a prime.
It is a super-2 number, since 2×64071254015532 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (6407125401503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3203562700776 + 3203562700777.
It is an arithmetic number, because the mean of its divisors is an integer number (3203562700777).
Almost surely, 26407125401553 is an apocalyptic number.
It is an amenable number.
6407125401553 is a deficient number, since it is larger than the sum of its proper divisors (1).
6407125401553 is an equidigital number, since it uses as much as digits as its factorization.
6407125401553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504000, while the sum is 43.
The spelling of 6407125401553 in words is "six trillion, four hundred seven billion, one hundred twenty-five million, four hundred one thousand, five hundred fifty-three".
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