Base | Representation |
---|---|
bin | 101110101000111000111… |
… | …0001011110010010010011 |
3 | 211200210022220212120012212 |
4 | 1131101301301132102103 |
5 | 1320010140000001042 |
6 | 21344414025542335 |
7 | 1231051530004442 |
oct | 135216161362223 |
9 | 24623286776185 |
10 | 6410000000147 |
11 | 2051513989987 |
12 | 8763740449ab |
13 | 3765ca688693 |
14 | 182362114d59 |
15 | b1b1373e482 |
hex | 5d471c5e493 |
6410000000147 has 16 divisors (see below), whose sum is σ = 6449864474880. Its totient is φ = 6370299448800.
The previous prime is 6410000000119. The next prime is 6410000000171. The reversal of 6410000000147 is 7410000000146.
It is a cyclic number.
It is not a de Polignac number, because 6410000000147 - 230 = 6408926258323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (6410000000447) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 116350754 + ... + 116405832.
It is an arithmetic number, because the mean of its divisors is an integer number (403116529680).
Almost surely, 26410000000147 is an apocalyptic number.
6410000000147 is a deficient number, since it is larger than the sum of its proper divisors (39864474733).
6410000000147 is a wasteful number, since it uses less digits than its factorization.
6410000000147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56554.
The product of its (nonzero) digits is 672, while the sum is 23.
Subtracting 6410000000147 from its reverse (7410000000146), we obtain a palindrome (999999999999).
The spelling of 6410000000147 in words is "six trillion, four hundred ten billion, one hundred forty-seven", and thus it is an aban number.
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