Base | Representation |
---|---|
bin | 1001000110111111001100010… |
… | …0111101010000000101000001 |
3 | 10010001121010122221012120102020 |
4 | 2101233303010331100011001 |
5 | 1133004131333244441301 |
6 | 10151143551325312053 |
7 | 252005552222626041 |
oct | 22157630475200501 |
9 | 3101533587176366 |
10 | 641001403515201 |
11 | 176274194459723 |
12 | 5ba86449105629 |
13 | 2168923307c691 |
14 | b4408c2339721 |
15 | 4e18db698c436 |
hex | 246fcc4f50141 |
641001403515201 has 8 divisors (see below), whose sum is σ = 854989962828960. Its totient is φ = 427173556605792.
The previous prime is 641001403515167. The next prime is 641001403515211. The reversal of 641001403515201 is 102515304100146.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 641001403515201 - 210 = 641001403514177 is a prime.
It is not an unprimeable number, because it can be changed into a prime (641001403515211) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40178091780 + ... + 40178107733.
It is an arithmetic number, because the mean of its divisors is an integer number (106873745353620).
Almost surely, 2641001403515201 is an apocalyptic number.
It is an amenable number.
641001403515201 is a deficient number, since it is larger than the sum of its proper divisors (213988559313759).
641001403515201 is a wasteful number, since it uses less digits than its factorization.
641001403515201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80356202175.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 641001403515201 its reverse (102515304100146), we get a palindrome (743516707615347).
The spelling of 641001403515201 in words is "six hundred forty-one trillion, one billion, four hundred three million, five hundred fifteen thousand, two hundred one".
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