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6413156124043 is a prime number
BaseRepresentation
bin101110101010010110111…
…1001001000010110001011
3211201002110212200021021111
41131110231321020112023
51320033120431432133
621350055132351151
71231222662424024
oct135245571102613
924632425607244
106413156124043
112052893494539
12876ab50154b7
133769b1504306
1418258135bc4b
15b1c4a8721cd
hex5d52de4858b

6413156124043 has 2 divisors, whose sum is σ = 6413156124044. Its totient is φ = 6413156124042.

The previous prime is 6413156123911. The next prime is 6413156124047. The reversal of 6413156124043 is 3404216513146.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-6413156124043 is a prime.

It is a super-2 number, since 2×64131561240432 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 6413156123987 and 6413156124005.

It is not a weakly prime, because it can be changed into another prime (6413156124047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3206578062021 + 3206578062022.

It is an arithmetic number, because the mean of its divisors is an integer number (3206578062022).

Almost surely, 26413156124043 is an apocalyptic number.

6413156124043 is a deficient number, since it is larger than the sum of its proper divisors (1).

6413156124043 is an equidigital number, since it uses as much as digits as its factorization.

6413156124043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 207360, while the sum is 40.

The spelling of 6413156124043 in words is "six trillion, four hundred thirteen billion, one hundred fifty-six million, one hundred twenty-four thousand, forty-three".