Base | Representation |
---|---|
bin | 11101001010111010100011… |
… | …01101001110010010001011 |
3 | 22102010100212022220001201212 |
4 | 32211131101231032102023 |
5 | 31401434424042001433 |
6 | 344232331320403335 |
7 | 16340306131155653 |
oct | 1645352155162213 |
9 | 272110768801655 |
10 | 64146707375243 |
11 | 19491514015139 |
12 | 724008a61654b |
13 | 29a4015a26cac |
14 | 11baa0800b363 |
15 | 76390a544d48 |
hex | 3a5751b4e48b |
64146707375243 has 2 divisors, whose sum is σ = 64146707375244. Its totient is φ = 64146707375242.
The previous prime is 64146707375197. The next prime is 64146707375249. The reversal of 64146707375243 is 34257370764146.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 64146707375243 - 28 = 64146707374987 is a prime.
It is a super-2 number, since 2×641467073752432 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (64146707375249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32073353687621 + 32073353687622.
It is an arithmetic number, because the mean of its divisors is an integer number (32073353687622).
Almost surely, 264146707375243 is an apocalyptic number.
64146707375243 is a deficient number, since it is larger than the sum of its proper divisors (1).
64146707375243 is an equidigital number, since it uses as much as digits as its factorization.
64146707375243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 71124480, while the sum is 59.
The spelling of 64146707375243 in words is "sixty-four trillion, one hundred forty-six billion, seven hundred seven million, three hundred seventy-five thousand, two hundred forty-three".
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