Base | Representation |
---|---|
bin | 111011110001101001… |
… | …011010001110000001 |
3 | 20010200001222010010201 |
4 | 323301221122032001 |
5 | 2022422012101442 |
6 | 45252515325201 |
7 | 4431350334511 |
oct | 736151321601 |
9 | 203601863121 |
10 | 64183706497 |
11 | 25247035739 |
12 | 10532bb0801 |
13 | 608b44c871 |
14 | 316c387841 |
15 | 1a09bb47b7 |
hex | ef1a5a381 |
64183706497 has 2 divisors, whose sum is σ = 64183706498. Its totient is φ = 64183706496.
The previous prime is 64183706467. The next prime is 64183706501. The reversal of 64183706497 is 79460738146.
64183706497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 64150251841 + 33454656 = 253279^2 + 5784^2 .
It is a cyclic number.
It is not a de Polignac number, because 64183706497 - 27 = 64183706369 is a prime.
It is a super-2 number, since 2×641837064972 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (64183706407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32091853248 + 32091853249.
It is an arithmetic number, because the mean of its divisors is an integer number (32091853249).
Almost surely, 264183706497 is an apocalyptic number.
It is an amenable number.
64183706497 is a deficient number, since it is larger than the sum of its proper divisors (1).
64183706497 is an equidigital number, since it uses as much as digits as its factorization.
64183706497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6096384, while the sum is 55.
The spelling of 64183706497 in words is "sixty-four billion, one hundred eighty-three million, seven hundred six thousand, four hundred ninety-seven".
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