Base | Representation |
---|---|
bin | 111011110010001011… |
… | …000000001111101001 |
3 | 20010200200112112101112 |
4 | 323302023000033221 |
5 | 2022431240404001 |
6 | 45253432200105 |
7 | 4431515233451 |
oct | 736213001751 |
9 | 203620475345 |
10 | 64192513001 |
11 | 25251000141 |
12 | 10535b39035 |
13 | 6090214106 |
14 | 316d5dad61 |
15 | 1a0a853cbb |
hex | ef22c03e9 |
64192513001 has 4 divisors (see below), whose sum is σ = 64202073600. Its totient is φ = 64182952404.
The previous prime is 64192512983. The next prime is 64192513039. The reversal of 64192513001 is 10031529146.
64192513001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10031529146 = 2 ⋅5015764573.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-64192513001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (64192513201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4770221 + ... + 4783658.
It is an arithmetic number, because the mean of its divisors is an integer number (16050518400).
Almost surely, 264192513001 is an apocalyptic number.
It is an amenable number.
64192513001 is a deficient number, since it is larger than the sum of its proper divisors (9560599).
64192513001 is an equidigital number, since it uses as much as digits as its factorization.
64192513001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9560598.
The product of its (nonzero) digits is 6480, while the sum is 32.
The spelling of 64192513001 in words is "sixty-four billion, one hundred ninety-two million, five hundred thirteen thousand, one".
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