Base | Representation |
---|---|
bin | 10010101011110101111… |
… | …11000010100101011001 |
3 | 2021101011000121121211222 |
4 | 21111322333002211121 |
5 | 41004320422114423 |
6 | 1210534212501425 |
7 | 64245456323555 |
oct | 11257277024531 |
9 | 2241130547758 |
10 | 642013473113 |
11 | 228304960801 |
12 | a451501a875 |
13 | 48706bc377c |
14 | 23106016865 |
15 | 11a784c93c8 |
hex | 957afc2959 |
642013473113 has 4 divisors (see below), whose sum is σ = 642721316880. Its totient is φ = 641305629348.
The previous prime is 642013473109. The next prime is 642013473131. The reversal of 642013473113 is 311374310246.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 642013473113 - 22 = 642013473109 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (642013473133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353920523 + ... + 353922336.
It is an arithmetic number, because the mean of its divisors is an integer number (160680329220).
Almost surely, 2642013473113 is an apocalyptic number.
It is an amenable number.
642013473113 is a deficient number, since it is larger than the sum of its proper divisors (707843767).
642013473113 is an equidigital number, since it uses as much as digits as its factorization.
642013473113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 707843766.
The product of its (nonzero) digits is 36288, while the sum is 35.
Adding to 642013473113 its reverse (311374310246), we get a palindrome (953387783359).
The spelling of 642013473113 in words is "six hundred forty-two billion, thirteen million, four hundred seventy-three thousand, one hundred thirteen".
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