Base | Representation |
---|---|
bin | 101110101110000110110… |
… | …0110111000100001100011 |
3 | 211201212020202221021021022 |
4 | 1131130031212320201203 |
5 | 1320201111311414243 |
6 | 21353505515120055 |
7 | 1231626300610022 |
oct | 135341546704143 |
9 | 24655222837238 |
10 | 6421204404323 |
11 | 2056243538645 |
12 | 87858044302b |
13 | 377694a4cb37 |
14 | 182b061d28b9 |
15 | b206c207b68 |
hex | 5d70d9b8863 |
6421204404323 has 2 divisors, whose sum is σ = 6421204404324. Its totient is φ = 6421204404322.
The previous prime is 6421204404271. The next prime is 6421204404343. The reversal of 6421204404323 is 3234044021246.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6421204404323 - 218 = 6421204142179 is a prime.
It is a super-2 number, since 2×64212044043232 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (6421204404343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3210602202161 + 3210602202162.
It is an arithmetic number, because the mean of its divisors is an integer number (3210602202162).
Almost surely, 26421204404323 is an apocalyptic number.
6421204404323 is a deficient number, since it is larger than the sum of its proper divisors (1).
6421204404323 is an equidigital number, since it uses as much as digits as its factorization.
6421204404323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 6421204404323 its reverse (3234044021246), we get a palindrome (9655248425569).
The spelling of 6421204404323 in words is "six trillion, four hundred twenty-one billion, two hundred four million, four hundred four thousand, three hundred twenty-three".
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