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6421320257377 is a prime number
BaseRepresentation
bin101110101110001010010…
…0000110100111101100001
3211201212112211221012210011
41131130110200310331201
51320201330441214002
621353525214204521
71231632205420024
oct135342440647541
924655484835704
106421320257377
1120562a2977773
128785b31b3741
133776b2a5433c
14182b1774d1bb
15b207748e8d7
hex5d714834f61

6421320257377 has 2 divisors, whose sum is σ = 6421320257378. Its totient is φ = 6421320257376.

The previous prime is 6421320257321. The next prime is 6421320257393. The reversal of 6421320257377 is 7737520231246.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6075022139536 + 346298117841 = 2464756^2 + 588471^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-6421320257377 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 6421320257377.

It is not a weakly prime, because it can be changed into another prime (6421320257777) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3210660128688 + 3210660128689.

It is an arithmetic number, because the mean of its divisors is an integer number (3210660128689).

Almost surely, 26421320257377 is an apocalyptic number.

It is an amenable number.

6421320257377 is a deficient number, since it is larger than the sum of its proper divisors (1).

6421320257377 is an equidigital number, since it uses as much as digits as its factorization.

6421320257377 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2963520, while the sum is 49.

The spelling of 6421320257377 in words is "six trillion, four hundred twenty-one billion, three hundred twenty million, two hundred fifty-seven thousand, three hundred seventy-seven".