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642136403 is a prime number
BaseRepresentation
bin100110010001100…
…011100101010011
31122202021220112202
4212101203211103
52303341331103
6143415113415
721625032536
oct4621434523
91582256482
10642136403
112aa518647
1215b07286b
13a305c98c
14613d4a1d
153b592988
hex26463953

642136403 has 2 divisors, whose sum is σ = 642136404. Its totient is φ = 642136402.

The previous prime is 642136373. The next prime is 642136441. The reversal of 642136403 is 304631246.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 642136403 - 210 = 642135379 is a prime.

It is a super-3 number, since 3×6421364033 (a number of 27 digits) contains 333 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (642136303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 321068201 + 321068202.

It is an arithmetic number, because the mean of its divisors is an integer number (321068202).

Almost surely, 2642136403 is an apocalyptic number.

642136403 is a deficient number, since it is larger than the sum of its proper divisors (1).

642136403 is an equidigital number, since it uses as much as digits as its factorization.

642136403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 29.

The square root of 642136403 is about 25340.4104741814. The cubic root of 642136403 is about 862.7317153246.

Adding to 642136403 its reverse (304631246), we get a palindrome (946767649).

It can be divided in two parts, 6421 and 36403, that added together give a palindrome (42824).

The spelling of 642136403 in words is "six hundred forty-two million, one hundred thirty-six thousand, four hundred three".