642186113 has 2 divisors, whose sum is σ = 642186114. Its totient is φ = 642186112.

The previous prime is 642186079. The next prime is 642186131. The reversal of 642186113 is 311681246.

642186113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (642186131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 493150849 + 149035264 = 22207^2 + 12208^2 .

642186113 is a truncatable prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-642186113 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 642186113.

It is not a weakly prime, because it can be changed into another prime (642186133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 321093056 + 321093057.

It is an arithmetic number, because the mean of its divisors is an integer number (321093057).

Almost surely, 2^642186113 is an apocalyptic number.

It is an amenable number.

642186113 is a deficient number, since it is larger than the sum of its proper divisors (1).

642186113 is an equidigital number, since it uses as much as digits as its factorization.

642186113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 32.

The square root of 642186113 is about 25341.3912996110. The cubic root of 642186113 is about 862.7539770988.

The spelling of 642186113 in words is "six hundred forty-two million, one hundred eighty-six thousand, one hundred thirteen".