Base | Representation |
---|---|
bin | 10010101101000101111… |
… | …00111001110010101011 |
3 | 2021102212202022222210212 |
4 | 21112202330321302223 |
5 | 41012204101021301 |
6 | 1211124524331335 |
7 | 64301210606642 |
oct | 11264274716253 |
9 | 2242782288725 |
10 | 642684001451 |
11 | 228619400658 |
12 | a46816a3b4b |
13 | 487b2ab44bb |
14 | 2316b0bc359 |
15 | 11ab72c94bb |
hex | 95a2f39cab |
642684001451 has 2 divisors, whose sum is σ = 642684001452. Its totient is φ = 642684001450.
The previous prime is 642684001409. The next prime is 642684001457. The reversal of 642684001451 is 154100486246.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-642684001451 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 642684001399 and 642684001408.
It is not a weakly prime, because it can be changed into another prime (642684001457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 321342000725 + 321342000726.
It is an arithmetic number, because the mean of its divisors is an integer number (321342000726).
Almost surely, 2642684001451 is an apocalyptic number.
642684001451 is a deficient number, since it is larger than the sum of its proper divisors (1).
642684001451 is an equidigital number, since it uses as much as digits as its factorization.
642684001451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 184320, while the sum is 41.
Adding to 642684001451 its reverse (154100486246), we get a palindrome (796784487697).
The spelling of 642684001451 in words is "six hundred forty-two billion, six hundred eighty-four million, one thousand, four hundred fifty-one".
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