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643210114153 is a prime number
BaseRepresentation
bin10010101110000100100…
…11110111010001101001
32021111020102022021202111
421113002103313101221
541014243242123103
61211253041002321
764320226522135
oct11270223672151
92244212267674
10643210114153
11228869382942
12a47a99233a1
1348867ab00a9
14231bad103c5
1511ae859e86d
hex95c24f7469

643210114153 has 2 divisors, whose sum is σ = 643210114154. Its totient is φ = 643210114152.

The previous prime is 643210114123. The next prime is 643210114177. The reversal of 643210114153 is 351411012346.

643210114153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 443913047824 + 199297066329 = 666268^2 + 446427^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-643210114153 is a prime.

It is not a weakly prime, because it can be changed into another prime (643210114123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 321605057076 + 321605057077.

It is an arithmetic number, because the mean of its divisors is an integer number (321605057077).

Almost surely, 2643210114153 is an apocalyptic number.

It is an amenable number.

643210114153 is a deficient number, since it is larger than the sum of its proper divisors (1).

643210114153 is an equidigital number, since it uses as much as digits as its factorization.

643210114153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 643210114153 its reverse (351411012346), we get a palindrome (994621126499).

The spelling of 643210114153 in words is "six hundred forty-three billion, two hundred ten million, one hundred fourteen thousand, one hundred fifty-three".