Base | Representation |
---|---|
bin | 10010101110000100100… |
… | …11110111010001101001 |
3 | 2021111020102022021202111 |
4 | 21113002103313101221 |
5 | 41014243242123103 |
6 | 1211253041002321 |
7 | 64320226522135 |
oct | 11270223672151 |
9 | 2244212267674 |
10 | 643210114153 |
11 | 228869382942 |
12 | a47a99233a1 |
13 | 48867ab00a9 |
14 | 231bad103c5 |
15 | 11ae859e86d |
hex | 95c24f7469 |
643210114153 has 2 divisors, whose sum is σ = 643210114154. Its totient is φ = 643210114152.
The previous prime is 643210114123. The next prime is 643210114177. The reversal of 643210114153 is 351411012346.
643210114153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 443913047824 + 199297066329 = 666268^2 + 446427^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-643210114153 is a prime.
It is not a weakly prime, because it can be changed into another prime (643210114123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 321605057076 + 321605057077.
It is an arithmetic number, because the mean of its divisors is an integer number (321605057077).
Almost surely, 2643210114153 is an apocalyptic number.
It is an amenable number.
643210114153 is a deficient number, since it is larger than the sum of its proper divisors (1).
643210114153 is an equidigital number, since it uses as much as digits as its factorization.
643210114153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 643210114153 its reverse (351411012346), we get a palindrome (994621126499).
The spelling of 643210114153 in words is "six hundred forty-three billion, two hundred ten million, one hundred fourteen thousand, one hundred fifty-three".
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