Base | Representation |
---|---|
bin | 11101010011000001010011… |
… | …10101111001010110100011 |
3 | 22110002222201202102011011221 |
4 | 32221200221311321112203 |
5 | 31421020313111400103 |
6 | 345004311125115511 |
7 | 16366365540464011 |
oct | 1651405165712643 |
9 | 273088652364157 |
10 | 64425211434403 |
11 | 19589640324976 |
12 | 7286054b58b97 |
13 | 29c436b27a481 |
14 | 11ca2a82dd8b1 |
15 | 76acaa9911bd |
hex | 3a9829d795a3 |
64425211434403 has 2 divisors, whose sum is σ = 64425211434404. Its totient is φ = 64425211434402.
The previous prime is 64425211434377. The next prime is 64425211434413. The reversal of 64425211434403 is 30443411252446.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 64425211434403 - 213 = 64425211426211 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 64425211434403.
It is not a weakly prime, because it can be changed into another prime (64425211434413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32212605717201 + 32212605717202.
It is an arithmetic number, because the mean of its divisors is an integer number (32212605717202).
Almost surely, 264425211434403 is an apocalyptic number.
64425211434403 is a deficient number, since it is larger than the sum of its proper divisors (1).
64425211434403 is an equidigital number, since it uses as much as digits as its factorization.
64425211434403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1105920, while the sum is 43.
Adding to 64425211434403 its reverse (30443411252446), we get a palindrome (94868622686849).
The spelling of 64425211434403 in words is "sixty-four trillion, four hundred twenty-five billion, two hundred eleven million, four hundred thirty-four thousand, four hundred three".
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