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64520614641433 is a prime number
BaseRepresentation
bin11101010101110011000000…
…10100001111111100011001
322110110002222120101012221011
432222321200110033330121
531424101204322011213
6345120210003013521
716406313656404516
oct1652714024177431
9273402876335834
1064520614641433
1119616047a09415
1272a063b36a2a1
132a00363623572
1411d0b58a5a30d
1576d4e136d03d
hex3aae6050ff19

64520614641433 has 2 divisors, whose sum is σ = 64520614641434. Its totient is φ = 64520614641432.

The previous prime is 64520614641403. The next prime is 64520614641451. The reversal of 64520614641433 is 33414641602546.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 54188266567824 + 10332348073609 = 7361268^2 + 3214397^2 .

It is a cyclic number.

It is not a de Polignac number, because 64520614641433 - 233 = 64512024706841 is a prime.

It is a super-2 number, since 2×645206146414332 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (64520614641403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32260307320716 + 32260307320717.

It is an arithmetic number, because the mean of its divisors is an integer number (32260307320717).

Almost surely, 264520614641433 is an apocalyptic number.

It is an amenable number.

64520614641433 is a deficient number, since it is larger than the sum of its proper divisors (1).

64520614641433 is an equidigital number, since it uses as much as digits as its factorization.

64520614641433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4976640, while the sum is 49.

The spelling of 64520614641433 in words is "sixty-four trillion, five hundred twenty billion, six hundred fourteen million, six hundred forty-one thousand, four hundred thirty-three".