Base | Representation |
---|---|
bin | 101110111101001110101… |
… | …1000001001110011111011 |
3 | 211211222002010211010001022 |
4 | 1131322131120021303323 |
5 | 1321214114343430042 |
6 | 21420440310213055 |
7 | 1234156144240121 |
oct | 135723530116373 |
9 | 24758063733038 |
10 | 6453681233147 |
11 | 2068a99899845 |
12 | 88292495418b |
13 | 37a76c2c0705 |
14 | 184507579911 |
15 | b2d1d4d1cd2 |
hex | 5de9d609cfb |
6453681233147 has 2 divisors, whose sum is σ = 6453681233148. Its totient is φ = 6453681233146.
The previous prime is 6453681233143. The next prime is 6453681233171. The reversal of 6453681233147 is 7413321863546.
6453681233147 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 6453681233147 - 22 = 6453681233143 is a prime.
It is not a weakly prime, because it can be changed into another prime (6453681233143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3226840616573 + 3226840616574.
It is an arithmetic number, because the mean of its divisors is an integer number (3226840616574).
Almost surely, 26453681233147 is an apocalyptic number.
6453681233147 is a deficient number, since it is larger than the sum of its proper divisors (1).
6453681233147 is an equidigital number, since it uses as much as digits as its factorization.
6453681233147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8709120, while the sum is 53.
The spelling of 6453681233147 in words is "six trillion, four hundred fifty-three billion, six hundred eighty-one million, two hundred thirty-three thousand, one hundred forty-seven".
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