Base | Representation |
---|---|
bin | 1100000010110100… |
… | …11001101011101001 |
3 | 121200122012102000121 |
4 | 12001122121223221 |
5 | 101220313232342 |
6 | 2545344003241 |
7 | 316144234432 |
oct | 60132315351 |
9 | 17618172017 |
10 | 6466149097 |
11 | 2818a77581 |
12 | 1305600521 |
13 | 7c082b135 |
14 | 454ab2489 |
15 | 27ca16067 |
hex | 181699ae9 |
6466149097 has 2 divisors, whose sum is σ = 6466149098. Its totient is φ = 6466149096.
The previous prime is 6466149061. The next prime is 6466149139. The reversal of 6466149097 is 7909416646.
6466149097 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5720804496 + 745344601 = 75636^2 + 27301^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6466149097 is a prime.
It is a super-2 number, since 2×64661490972 = 83622168289267830818, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (6466149047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3233074548 + 3233074549.
It is an arithmetic number, because the mean of its divisors is an integer number (3233074549).
Almost surely, 26466149097 is an apocalyptic number.
It is an amenable number.
6466149097 is a deficient number, since it is larger than the sum of its proper divisors (1).
6466149097 is an equidigital number, since it uses as much as digits as its factorization.
6466149097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 52.
The square root of 6466149097 is about 80412.3690547667. The cubic root of 6466149097 is about 1863.0102234227.
The spelling of 6466149097 in words is "six billion, four hundred sixty-six million, one hundred forty-nine thousand, ninety-seven".
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