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64712425441 is a prime number
BaseRepresentation
bin111100010001001010…
…010011111111100001
320012000220211211011211
4330101022103333201
52030012340103231
645421203510121
74450430353246
oct742112237741
9205026754154
1064712425441
1125498528044
1210660088341
136143b4b801
1431bc6975cd
151a3b301eb1
hexf11293fe1

64712425441 has 2 divisors, whose sum is σ = 64712425442. Its totient is φ = 64712425440.

The previous prime is 64712425423. The next prime is 64712425447. The reversal of 64712425441 is 14452421746.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57166897216 + 7545528225 = 239096^2 + 86865^2 .

It is a cyclic number.

It is not a de Polignac number, because 64712425441 - 25 = 64712425409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 64712425394 and 64712425403.

It is not a weakly prime, because it can be changed into another prime (64712425447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32356212720 + 32356212721.

It is an arithmetic number, because the mean of its divisors is an integer number (32356212721).

Almost surely, 264712425441 is an apocalyptic number.

It is an amenable number.

64712425441 is a deficient number, since it is larger than the sum of its proper divisors (1).

64712425441 is an equidigital number, since it uses as much as digits as its factorization.

64712425441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 215040, while the sum is 40.

The spelling of 64712425441 in words is "sixty-four billion, seven hundred twelve million, four hundred twenty-five thousand, four hundred forty-one".