Base | Representation |
---|---|
bin | 11101100001010000010100… |
… | …11101111110011101111011 |
3 | 22111211202011222011210120110 |
4 | 32300220022131332131323 |
5 | 32002024002200420242 |
6 | 350021120053355403 |
7 | 16446622102216224 |
oct | 1660501235763573 |
9 | 274752158153513 |
10 | 64914311341947 |
11 | 197580064925a1 |
12 | 73449b3638b63 |
13 | 2a2b5160b12a2 |
14 | 1205c25a1c24b |
15 | 7788846bc39c |
hex | 3b0a0a77e77b |
64914311341947 has 4 divisors (see below), whose sum is σ = 86552415122600. Its totient is φ = 43276207561296.
The previous prime is 64914311341927. The next prime is 64914311341963. The reversal of 64914311341947 is 74914311341946.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 64914311341947 - 215 = 64914311309179 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (64914311341927) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10819051890322 + ... + 10819051890327.
It is an arithmetic number, because the mean of its divisors is an integer number (21638103780650).
Almost surely, 264914311341947 is an apocalyptic number.
64914311341947 is a deficient number, since it is larger than the sum of its proper divisors (21638103780653).
64914311341947 is a wasteful number, since it uses less digits than its factorization.
64914311341947 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21638103780652.
The product of its digits is 7838208, while the sum is 57.
Subtracting 64914311341947 from its reverse (74914311341946), we obtain a palindrome (9999999999999).
The spelling of 64914311341947 in words is "sixty-four trillion, nine hundred fourteen billion, three hundred eleven million, three hundred forty-one thousand, nine hundred forty-seven".
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