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650490233153 is a prime number
BaseRepresentation
bin10010111011101000011…
…11010100000101000001
32022012000210010122120112
421131310033110011001
541124200444430103
61214455303121105
764665516515645
oct11356417240501
92265023118515
10650490233153
11230964862012
12a609ba43195
1349458142907
14236abb46c25
1511dc279bcd8
hex97743d4141

650490233153 has 2 divisors, whose sum is σ = 650490233154. Its totient is φ = 650490233152.

The previous prime is 650490233149. The next prime is 650490233161. The reversal of 650490233153 is 351332094056.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 622216483249 + 28273749904 = 788807^2 + 168148^2 .

It is a cyclic number.

It is not a de Polignac number, because 650490233153 - 22 = 650490233149 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 650490233153.

It is not a weakly prime, because it can be changed into another prime (650490233143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325245116576 + 325245116577.

It is an arithmetic number, because the mean of its divisors is an integer number (325245116577).

Almost surely, 2650490233153 is an apocalyptic number.

It is an amenable number.

650490233153 is a deficient number, since it is larger than the sum of its proper divisors (1).

650490233153 is an equidigital number, since it uses as much as digits as its factorization.

650490233153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 291600, while the sum is 41.

The spelling of 650490233153 in words is "six hundred fifty billion, four hundred ninety million, two hundred thirty-three thousand, one hundred fifty-three".