Base | Representation |
---|---|
bin | 11101100101001101010000… |
… | …00011010010101100110001 |
3 | 22112022201200020212022020111 |
4 | 32302212220003102230301 |
5 | 32011240100334230413 |
6 | 350203334125141321 |
7 | 16462500045335524 |
oct | 1662465003225461 |
9 | 275281606768214 |
10 | 65050099133233 |
11 | 197aa657120a05 |
12 | 736718a6ba841 |
13 | 2a3b2760b1596 |
14 | 120c627a56bbb |
15 | 77c1806ebd3d |
hex | 3b29a80d2b31 |
65050099133233 has 4 divisors (see below), whose sum is σ = 65052527943168. Its totient is φ = 65047670323300.
The previous prime is 65050099133191. The next prime is 65050099133267. The reversal of 65050099133233 is 33233199005056.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 65050099133233 - 245 = 29865727044401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (65050099133533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1214364793 + ... + 1214418358.
It is an arithmetic number, because the mean of its divisors is an integer number (16263131985792).
Almost surely, 265050099133233 is an apocalyptic number.
It is an amenable number.
65050099133233 is a deficient number, since it is larger than the sum of its proper divisors (2428809935).
65050099133233 is a wasteful number, since it uses less digits than its factorization.
65050099133233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2428809934.
The product of its (nonzero) digits is 1968300, while the sum is 49.
The spelling of 65050099133233 in words is "sixty-five trillion, fifty billion, ninety-nine million, one hundred thirty-three thousand, two hundred thirty-three".
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