Base | Representation |
---|---|
bin | 11101100101100000101000… |
… | …00111100011001100110001 |
3 | 22112100201112020220221211101 |
4 | 32302300110013203030301 |
5 | 32011422402020421223 |
6 | 350212214305244401 |
7 | 16463315615314624 |
oct | 1662602407431461 |
9 | 275321466827741 |
10 | 65060502123313 |
11 | 19804005363374 |
12 | 73691b2633701 |
13 | 2a3c243419308 |
14 | 120cd3351bdbb |
15 | 77c58db5e4ad |
hex | 3b2c141e3331 |
65060502123313 has 2 divisors, whose sum is σ = 65060502123314. Its totient is φ = 65060502123312.
The previous prime is 65060502123277. The next prime is 65060502123403. The reversal of 65060502123313 is 31332120506056.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 33908342209569 + 31152159913744 = 5823087^2 + 5581412^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-65060502123313 is a prime.
It is not a weakly prime, because it can be changed into another prime (65060502123413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32530251061656 + 32530251061657.
It is an arithmetic number, because the mean of its divisors is an integer number (32530251061657).
Almost surely, 265060502123313 is an apocalyptic number.
It is an amenable number.
65060502123313 is a deficient number, since it is larger than the sum of its proper divisors (1).
65060502123313 is an equidigital number, since it uses as much as digits as its factorization.
65060502123313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 97200, while the sum is 37.
Adding to 65060502123313 its reverse (31332120506056), we get a palindrome (96392622629369).
The spelling of 65060502123313 in words is "sixty-five trillion, sixty billion, five hundred two million, one hundred twenty-three thousand, three hundred thirteen".
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