Base | Representation |
---|---|
bin | 111100101001001110… |
… | …011001101100000011 |
3 | 20020002001112011212221 |
4 | 330221032121230003 |
5 | 2031324213304111 |
6 | 45525225031511 |
7 | 4463432101315 |
oct | 745116315403 |
9 | 206061464787 |
10 | 65116150531 |
11 | 25685407743 |
12 | 10753325597 |
13 | 61a96957b3 |
14 | 321a14b7b5 |
15 | 1a6199e371 |
hex | f29399b03 |
65116150531 has 2 divisors, whose sum is σ = 65116150532. Its totient is φ = 65116150530.
The previous prime is 65116150499. The next prime is 65116150543. The reversal of 65116150531 is 13505161156.
65116150531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 65116150531 - 25 = 65116150499 is a prime.
It is a super-2 number, since 2×651161505312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (65116150591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32558075265 + 32558075266.
It is an arithmetic number, because the mean of its divisors is an integer number (32558075266).
Almost surely, 265116150531 is an apocalyptic number.
65116150531 is a deficient number, since it is larger than the sum of its proper divisors (1).
65116150531 is an equidigital number, since it uses as much as digits as its factorization.
65116150531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 34.
The spelling of 65116150531 in words is "sixty-five billion, one hundred sixteen million, one hundred fifty thousand, five hundred thirty-one".
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