Base | Representation |
---|---|
bin | 101111011010100110101… |
… | …1010001100100111111001 |
3 | 212001222220111100211121120 |
4 | 1132311031122030213321 |
5 | 1323232313102213423 |
6 | 21505432103055453 |
7 | 1241551326620100 |
oct | 136651532144771 |
9 | 25058814324546 |
10 | 6516764101113 |
11 | 2092820497172 |
12 | 892bab141589 |
13 | 3836b3657a16 |
14 | 1875ad647037 |
15 | b47b16e6ee3 |
hex | 5ed4d68c9f9 |
6516764101113 has 24 divisors (see below), whose sum is σ = 10107768544128. Its totient is φ = 3723815674656.
The previous prime is 6516764101109. The next prime is 6516764101157. The reversal of 6516764101113 is 3111014676156.
It is not a de Polignac number, because 6516764101113 - 22 = 6516764101109 is a prime.
It is a super-3 number, since 3×65167641011133 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (6516764102113) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12753495 + ... + 13254627.
It is an arithmetic number, because the mean of its divisors is an integer number (421157022672).
Almost surely, 26516764101113 is an apocalyptic number.
It is an amenable number.
6516764101113 is a deficient number, since it is larger than the sum of its proper divisors (3591004443015).
6516764101113 is a wasteful number, since it uses less digits than its factorization.
6516764101113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 589613 (or 589606 counting only the distinct ones).
The product of its (nonzero) digits is 90720, while the sum is 42.
Adding to 6516764101113 its reverse (3111014676156), we get a palindrome (9627778777269).
The spelling of 6516764101113 in words is "six trillion, five hundred sixteen billion, seven hundred sixty-four million, one hundred one thousand, one hundred thirteen".
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