Base | Representation |
---|---|
bin | 11101101010001001111100… |
… | …00101110011110010100001 |
3 | 22112220222112022022022100202 |
4 | 32311010332011303302201 |
5 | 32022031301221200001 |
6 | 350413413132354545 |
7 | 16510666242610346 |
oct | 1665047605636241 |
9 | 275828468268322 |
10 | 65220120100001 |
11 | 19865774569789 |
12 | 739411a315a55 |
13 | 2a51300499b29 |
14 | 12169563ca7cd |
15 | 7817d1cd996b |
hex | 3b513e173ca1 |
65220120100001 has 4 divisors (see below), whose sum is σ = 65220179601600. Its totient is φ = 65220060598404.
The previous prime is 65220120099991. The next prime is 65220120100033. The reversal of 65220120100001 is 10000102102256.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 65220120100001 - 238 = 64945242193057 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (65220125100001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28075181 + ... + 30309338.
It is an arithmetic number, because the mean of its divisors is an integer number (16305044900400).
Almost surely, 265220120100001 is an apocalyptic number.
It is an amenable number.
65220120100001 is a deficient number, since it is larger than the sum of its proper divisors (59501599).
65220120100001 is a wasteful number, since it uses less digits than its factorization.
65220120100001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59501598.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 65220120100001 its reverse (10000102102256), we get a palindrome (75220222202257).
The spelling of 65220120100001 in words is "sixty-five trillion, two hundred twenty billion, one hundred twenty million, one hundred thousand, one".
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