Base | Representation |
---|---|
bin | 111100110000101010… |
… | …110000011010000011 |
3 | 20020101202111102021002 |
4 | 330300222300122003 |
5 | 2032103200233011 |
6 | 45545445322215 |
7 | 4466506361303 |
oct | 746052603203 |
9 | 206352442232 |
10 | 65241024131 |
11 | 25739948068 |
12 | 1078910636b |
13 | 61c9507aba |
14 | 322c975603 |
15 | 1a6c918c3b |
hex | f30ab0683 |
65241024131 has 4 divisors (see below), whose sum is σ = 66832268664. Its totient is φ = 63649779600.
The previous prime is 65241024119. The next prime is 65241024133. The reversal of 65241024131 is 13142014256.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 65241024131 - 230 = 64167282307 is a prime.
It is a super-2 number, since 2×652410241312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 65241024094 and 65241024103.
It is not an unprimeable number, because it can be changed into a prime (65241024133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 795622205 + ... + 795622286.
It is an arithmetic number, because the mean of its divisors is an integer number (16708067166).
Almost surely, 265241024131 is an apocalyptic number.
65241024131 is a deficient number, since it is larger than the sum of its proper divisors (1591244533).
65241024131 is a wasteful number, since it uses less digits than its factorization.
65241024131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1591244532.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 65241024131 its reverse (13142014256), we get a palindrome (78383038387).
The spelling of 65241024131 in words is "sixty-five billion, two hundred forty-one million, twenty-four thousand, one hundred thirty-one".
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