Base | Representation |
---|---|
bin | 101111100010000111011… |
… | …0110010010000100000001 |
3 | 212010112112122022021222201 |
4 | 1133010032312102010001 |
5 | 1324013331424234001 |
6 | 21521100434433201 |
7 | 1242662132622211 |
oct | 137041666220401 |
9 | 25115478267881 |
10 | 6532894368001 |
11 | 2099648616451 |
12 | 896151132801 |
13 | 3850843c1041 |
14 | 18829da08241 |
15 | b4e07870501 |
hex | 5f10ed92101 |
6532894368001 has 4 divisors (see below), whose sum is σ = 6534295379392. Its totient is φ = 6531493356612.
The previous prime is 6532894367981. The next prime is 6532894368047. The reversal of 6532894368001 is 1008634982356.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 6532894368001 - 213 = 6532894359809 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (6532894363001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 700498701 + ... + 700508026.
It is an arithmetic number, because the mean of its divisors is an integer number (1633573844848).
Almost surely, 26532894368001 is an apocalyptic number.
It is an amenable number.
6532894368001 is a deficient number, since it is larger than the sum of its proper divisors (1401011391).
6532894368001 is a wasteful number, since it uses less digits than its factorization.
6532894368001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1401011390.
The product of its (nonzero) digits is 7464960, while the sum is 55.
The spelling of 6532894368001 in words is "six trillion, five hundred thirty-two billion, eight hundred ninety-four million, three hundred sixty-eight thousand, one".
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