Base | Representation |
---|---|
bin | 1001010010101000101000101… |
… | …0010110001110101101010001 |
3 | 10011201221102202112201222112002 |
4 | 2110222022022112032231101 |
5 | 1141143442302221342423 |
6 | 10234311130553243345 |
7 | 254500033022516450 |
oct | 22452121226165521 |
9 | 3151842675658462 |
10 | 653808012684113 |
11 | 17a36146a469691 |
12 | 613b4458703555 |
13 | 220a7aa5a70761 |
14 | b764695d40b97 |
15 | 508c0a8017228 |
hex | 252a28a58eb51 |
653808012684113 has 4 divisors (see below), whose sum is σ = 747209157353280. Its totient is φ = 560406868014948.
The previous prime is 653808012684103. The next prime is 653808012684163. The reversal of 653808012684113 is 311486210808356.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 653808012684113 - 28 = 653808012683857 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (653808012684103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46700572334573 + ... + 46700572334586.
It is an arithmetic number, because the mean of its divisors is an integer number (186802289338320).
Almost surely, 2653808012684113 is an apocalyptic number.
It is an amenable number.
653808012684113 is a deficient number, since it is larger than the sum of its proper divisors (93401144669167).
653808012684113 is an equidigital number, since it uses as much as digits as its factorization.
653808012684113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93401144669166.
The product of its (nonzero) digits is 6635520, while the sum is 56.
The spelling of 653808012684113 in words is "six hundred fifty-three trillion, eight hundred eight billion, twelve million, six hundred eighty-four thousand, one hundred thirteen".
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