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6544049153 is a prime number
BaseRepresentation
bin1100001100000111…
…00100010000000001
3121220001210010210212
412012003210100001
5101400234033103
63001205403505
7321111333335
oct60603442001
917801703725
106544049153
112858a43a94
121327709595
13803a04745
1446118d7c5
152847a27d8
hex1860e4401

6544049153 has 2 divisors, whose sum is σ = 6544049154. Its totient is φ = 6544049152.

The previous prime is 6544049137. The next prime is 6544049167. The reversal of 6544049153 is 3519404456.

6544049153 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6450017344 + 94031809 = 80312^2 + 9697^2 .

It is a cyclic number.

It is not a de Polignac number, because 6544049153 - 24 = 6544049137 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 6544049153.

It is not a weakly prime, because it can be changed into another prime (6544049123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3272024576 + 3272024577.

It is an arithmetic number, because the mean of its divisors is an integer number (3272024577).

Almost surely, 26544049153 is an apocalyptic number.

It is an amenable number.

6544049153 is a deficient number, since it is larger than the sum of its proper divisors (1).

6544049153 is an equidigital number, since it uses as much as digits as its factorization.

6544049153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 41.

The square root of 6544049153 is about 80895.2974714847. The cubic root of 6544049153 is about 1870.4618334662.

The spelling of 6544049153 in words is "six billion, five hundred forty-four million, forty-nine thousand, one hundred fifty-three".