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6553114067147 = 22812872912787
BaseRepresentation
bin101111101011100010000…
…0010010100000011001011
3212012110201210020102210212
41133113010002110003023
51324331234200122042
621534243053031335
71244306163340334
oct137270402240313
925173653212725
106553114067147
1120a718406270a
1289a05478554b
13386c5745c46b
1418925b15d28b
15b56dca37482
hex5f5c40940cb

6553114067147 has 4 divisors (see below), whose sum is σ = 6555986982216. Its totient is φ = 6550241152080.

The previous prime is 6553114067119. The next prime is 6553114067161. The reversal of 6553114067147 is 7417604113556.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 6553114067147 - 26 = 6553114067083 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 6553114067095 and 6553114067104.

It is not an unprimeable number, because it can be changed into a prime (6553114067167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1436454113 + ... + 1436458674.

It is an arithmetic number, because the mean of its divisors is an integer number (1638996745554).

Almost surely, 26553114067147 is an apocalyptic number.

6553114067147 is a deficient number, since it is larger than the sum of its proper divisors (2872915069).

6553114067147 is a wasteful number, since it uses less digits than its factorization.

6553114067147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2872915068.

The product of its (nonzero) digits is 2116800, while the sum is 50.

The spelling of 6553114067147 in words is "six trillion, five hundred fifty-three billion, one hundred fourteen million, sixty-seven thousand, one hundred forty-seven".

Divisors: 1 2281 2872912787 6553114067147