Base | Representation |
---|---|
bin | 111101010010110100… |
… | …001011110010110011 |
3 | 20021212200111120221200 |
4 | 331102310023302303 |
5 | 2034241330432242 |
6 | 50122352422243 |
7 | 4516634045355 |
oct | 752264136263 |
9 | 207780446850 |
10 | 65813920947 |
11 | 25a03273a05 |
12 | 10908b47983 |
13 | 628b1040b8 |
14 | 3284aa50d5 |
15 | 1aa2d8104c |
hex | f52d0bcb3 |
65813920947 has 12 divisors (see below), whose sum is σ = 95119178544. Its totient is φ = 43850735280.
The previous prime is 65813920919. The next prime is 65813920999. The reversal of 65813920947 is 74902931856.
65813920947 is a `hidden beast` number, since 6 + 581 + 39 + 20 + 9 + 4 + 7 = 666.
It is not a de Polignac number, because 65813920947 - 222 = 65809726643 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 65813920893 and 65813920902.
It is not an unprimeable number, because it can be changed into a prime (65803920947) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2084463 + ... + 2115800.
It is an arithmetic number, because the mean of its divisors is an integer number (7926598212).
It is a 1-persistent number, because it is pandigital, but 2⋅65813920947 = 131627841894 is not.
Almost surely, 265813920947 is an apocalyptic number.
65813920947 is a deficient number, since it is larger than the sum of its proper divisors (29305257597).
65813920947 is a wasteful number, since it uses less digits than its factorization.
65813920947 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4202010 (or 4202007 counting only the distinct ones).
The product of its (nonzero) digits is 3265920, while the sum is 54.
The spelling of 65813920947 in words is "sixty-five billion, eight hundred thirteen million, nine hundred twenty thousand, nine hundred forty-seven".
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