Base | Representation |
---|---|
bin | 11110000100000100010000… |
… | …10011111010001100110011 |
3 | 22200002002120002022010121212 |
4 | 33002002020103322030303 |
5 | 32131123121411244111 |
6 | 352334413113110335 |
7 | 16632214632155246 |
oct | 1702021023721463 |
9 | 280062502263555 |
10 | 66110423540531 |
11 | 1a079300658967 |
12 | 74b87870b83ab |
13 | 2ab725609c586 |
14 | 1247a93a7b25d |
15 | 799a3cde698b |
hex | 3c20884fa333 |
66110423540531 has 2 divisors, whose sum is σ = 66110423540532. Its totient is φ = 66110423540530.
The previous prime is 66110423540353. The next prime is 66110423540597. The reversal of 66110423540531 is 13504532401166.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 66110423540531 - 218 = 66110423278387 is a prime.
It is a super-2 number, since 2×661104235405312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (66110423540831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33055211770265 + 33055211770266.
It is an arithmetic number, because the mean of its divisors is an integer number (33055211770266).
Almost surely, 266110423540531 is an apocalyptic number.
66110423540531 is a deficient number, since it is larger than the sum of its proper divisors (1).
66110423540531 is an equidigital number, since it uses as much as digits as its factorization.
66110423540531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 41.
Adding to 66110423540531 its reverse (13504532401166), we get a palindrome (79614955941697).
The spelling of 66110423540531 in words is "sixty-six trillion, one hundred ten billion, four hundred twenty-three million, five hundred forty thousand, five hundred thirty-one".
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