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66120433 is a prime number
BaseRepresentation
bin1111110000111…
…0101011110001
311121102021011221
43330032223301
5113411323213
610321105041
71432004641
oct374165361
9147367157
1066120433
1134361295
121a188181
1310910a22
148ad2521
155c1138d
hex3f0eaf1

66120433 has 2 divisors, whose sum is σ = 66120434. Its totient is φ = 66120432.

The previous prime is 66120419. The next prime is 66120473. The reversal of 66120433 is 33402166.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42810849 + 23309584 = 6543^2 + 4828^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-66120433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 66120398 and 66120407.

It is not a weakly prime, because it can be changed into another prime (66120473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33060216 + 33060217.

It is an arithmetic number, because the mean of its divisors is an integer number (33060217).

Almost surely, 266120433 is an apocalyptic number.

It is an amenable number.

66120433 is a deficient number, since it is larger than the sum of its proper divisors (1).

66120433 is an equidigital number, since it uses as much as digits as its factorization.

66120433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

The square root of 66120433 is about 8131.4471651730. The cubic root of 66120433 is about 404.3696601056.

Adding to 66120433 its reverse (33402166), we get a palindrome (99522599).

The spelling of 66120433 in words is "sixty-six million, one hundred twenty thousand, four hundred thirty-three".