Base | Representation |
---|---|
bin | 110000001011100111000… |
… | …1110001010011100100001 |
3 | 212110001112212121002022002 |
4 | 1200113032032022130201 |
5 | 1331443331113004213 |
6 | 22030035024253345 |
7 | 1252265304604241 |
oct | 140271616123441 |
9 | 25401485532262 |
10 | 6622004422433 |
11 | 2123415952234 |
12 | 8ab47ba71255 |
13 | 3905b5a2a1ba |
14 | 18c714645b21 |
15 | b73c0a09658 |
hex | 605ce38a721 |
6622004422433 has 2 divisors, whose sum is σ = 6622004422434. Its totient is φ = 6622004422432.
The previous prime is 6622004422381. The next prime is 6622004422543. The reversal of 6622004422433 is 3342244002266.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6596714517649 + 25289904784 = 2568407^2 + 159028^2 .
It is a cyclic number.
It is not a de Polignac number, because 6622004422433 - 28 = 6622004422177 is a prime.
It is not a weakly prime, because it can be changed into another prime (6622004422633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3311002211216 + 3311002211217.
It is an arithmetic number, because the mean of its divisors is an integer number (3311002211217).
Almost surely, 26622004422433 is an apocalyptic number.
It is an amenable number.
6622004422433 is a deficient number, since it is larger than the sum of its proper divisors (1).
6622004422433 is an equidigital number, since it uses as much as digits as its factorization.
6622004422433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 331776, while the sum is 38.
Adding to 6622004422433 its reverse (3342244002266), we get a palindrome (9964248424699).
The spelling of 6622004422433 in words is "six trillion, six hundred twenty-two billion, four million, four hundred twenty-two thousand, four hundred thirty-three".
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