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666733340753 is a prime number
BaseRepresentation
bin10011011001111000110…
…01110110100001010001
32100201221210102000022022
421230330121312201101
541410432213401003
61230143145221225
766112162613534
oct11547431664121
92321853360268
10666733340753
1123783a653187
12a9273791815
134ab4639729c
14243ad0bca1b
15125237b4738
hex9b3c676851

666733340753 has 2 divisors, whose sum is σ = 666733340754. Its totient is φ = 666733340752.

The previous prime is 666733340731. The next prime is 666733340761. The reversal of 666733340753 is 357043337666.

666733340753 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 657061011649 + 9672329104 = 810593^2 + 98348^2 .

It is a cyclic number.

It is not a de Polignac number, because 666733340753 - 210 = 666733339729 is a prime.

It is a super-3 number, since 3×6667333407533 (a number of 36 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 666733340695 and 666733340704.

It is not a weakly prime, because it can be changed into another prime (666733240753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 333366670376 + 333366670377.

It is an arithmetic number, because the mean of its divisors is an integer number (333366670377).

Almost surely, 2666733340753 is an apocalyptic number.

It is an amenable number.

666733340753 is a deficient number, since it is larger than the sum of its proper divisors (1).

666733340753 is an equidigital number, since it uses as much as digits as its factorization.

666733340753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17146080, while the sum is 53.

The spelling of 666733340753 in words is "six hundred sixty-six billion, seven hundred thirty-three million, three hundred forty thousand, seven hundred fifty-three".