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6671210055217 is a prime number
BaseRepresentation
bin110000100010100001100…
…0110110000011000110001
3212121202120002200012221221
41201011003012300120301
51333300114233231332
622104413411545041
71255656542563501
oct141050306603061
925552502605857
106671210055217
112142276181454
128b8b128bb181
13395128039b46
14190c61675a01
15b880078b297
hex611431b0631

6671210055217 has 2 divisors, whose sum is σ = 6671210055218. Its totient is φ = 6671210055216.

The previous prime is 6671210055127. The next prime is 6671210055269. The reversal of 6671210055217 is 7125500121766.

Together with previous prime (6671210055127) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5699564165376 + 971645889841 = 2387376^2 + 985721^2 .

It is a cyclic number.

It is not a de Polignac number, because 6671210055217 - 27 = 6671210055089 is a prime.

It is not a weakly prime, because it can be changed into another prime (6671210055017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3335605027608 + 3335605027609.

It is an arithmetic number, because the mean of its divisors is an integer number (3335605027609).

Almost surely, 26671210055217 is an apocalyptic number.

It is an amenable number.

6671210055217 is a deficient number, since it is larger than the sum of its proper divisors (1).

6671210055217 is an equidigital number, since it uses as much as digits as its factorization.

6671210055217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 176400, while the sum is 43.

The spelling of 6671210055217 in words is "six trillion, six hundred seventy-one billion, two hundred ten million, fifty-five thousand, two hundred seventeen".