Base | Representation |
---|---|
bin | 11110010110001101111111… |
… | …10011011001110001110011 |
3 | 22202021201102220020222102001 |
4 | 33023012333303121301303 |
5 | 32221332441422114024 |
6 | 353533122251434431 |
7 | 20025244552334365 |
oct | 1713067763316163 |
9 | 282251386228361 |
10 | 66734124801139 |
11 | 1a299868771344 |
12 | 759962b455a17 |
13 | 2b3100217a033 |
14 | 1269d3d9d4d35 |
15 | 7aad938e5244 |
hex | 3cb1bfcd9c73 |
66734124801139 has 2 divisors, whose sum is σ = 66734124801140. Its totient is φ = 66734124801138.
The previous prime is 66734124801103. The next prime is 66734124801173. The reversal of 66734124801139 is 93110842143766.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 66734124801139 - 215 = 66734124768371 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 66734124801139.
It is not a weakly prime, because it can be changed into another prime (66734124807139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33367062400569 + 33367062400570.
It is an arithmetic number, because the mean of its divisors is an integer number (33367062400570).
Almost surely, 266734124801139 is an apocalyptic number.
66734124801139 is a deficient number, since it is larger than the sum of its proper divisors (1).
66734124801139 is an equidigital number, since it uses as much as digits as its factorization.
66734124801139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5225472, while the sum is 55.
The spelling of 66734124801139 in words is "sixty-six trillion, seven hundred thirty-four billion, one hundred twenty-four million, eight hundred one thousand, one hundred thirty-nine".
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