Base | Representation |
---|---|
bin | 110000100110110100100… |
… | …0010000101011111010011 |
3 | 212122122101002111000002201 |
4 | 1201031221002011133103 |
5 | 1333423013143042411 |
6 | 22112541114224031 |
7 | 1256434303426525 |
oct | 141155102053723 |
9 | 25578332430081 |
10 | 6680436299731 |
11 | 2146180150517 |
12 | 8ba868725017 |
13 | 395c68632c1c |
14 | 191498b41a15 |
15 | b8b907583c1 |
hex | 613690857d3 |
6680436299731 has 2 divisors, whose sum is σ = 6680436299732. Its totient is φ = 6680436299730.
The previous prime is 6680436299609. The next prime is 6680436299773. The reversal of 6680436299731 is 1379926340866.
6680436299731 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 6680436299731 - 211 = 6680436297683 is a prime.
It is a super-2 number, since 2×66804362997312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (6680436299231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3340218149865 + 3340218149866.
It is an arithmetic number, because the mean of its divisors is an integer number (3340218149866).
Almost surely, 26680436299731 is an apocalyptic number.
6680436299731 is a deficient number, since it is larger than the sum of its proper divisors (1).
6680436299731 is an equidigital number, since it uses as much as digits as its factorization.
6680436299731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 70543872, while the sum is 64.
The spelling of 6680436299731 in words is "six trillion, six hundred eighty billion, four hundred thirty-six million, two hundred ninety-nine thousand, seven hundred thirty-one".
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